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Is there a defined priority for pattern matching?


Using a PatternTest versus a Condition for pattern matchingIs pure pattern matching without PatternTest and Condition Turing-complete?Classifying poker hands by pattern matchingMore general pattern fails to match everything the more specific pattern does.Detecting a more general patternPattern matching to head with HoldFirstHow to visualize pattern matching process?Pattern matching an expression involving TimesCompare arrays using custom pattern matchingPattern Match Bug with Equals?













6












$begingroup$


If you define a function g, like so:



g[x_?EvenQ] := "even"    
g[x_?NumberQ] := "number"


why will Mathematica always return g[2] == "Even", even though NumberQ[2] == True?



More specifically, is there a defined order in which Mathematica will try to match function cases? Does it evaluate the most specific match first?










share|improve this question









New contributor




wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    g[x_NumberQ] means to match arguments with the head NumberQ. What you want is to match arguments such that NumberQ[x] is True, which is g[x_?NumberQ]. Look up PatternTest[]. (Before you make this correction, make sure to run Clear[g] first.)
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    That's right---fixed.
    $endgroup$
    – wgoodall01
    14 hours ago






  • 2




    $begingroup$
    Once you have made this fix, evaluate DownValues[g]; that should give a hint as to which case gets applied first. Generally, it tries to put special cases first before general ones.
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    Or just execute ?g to see the order of the definitions.
    $endgroup$
    – Roman
    12 hours ago
















6












$begingroup$


If you define a function g, like so:



g[x_?EvenQ] := "even"    
g[x_?NumberQ] := "number"


why will Mathematica always return g[2] == "Even", even though NumberQ[2] == True?



More specifically, is there a defined order in which Mathematica will try to match function cases? Does it evaluate the most specific match first?










share|improve this question









New contributor




wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    g[x_NumberQ] means to match arguments with the head NumberQ. What you want is to match arguments such that NumberQ[x] is True, which is g[x_?NumberQ]. Look up PatternTest[]. (Before you make this correction, make sure to run Clear[g] first.)
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    That's right---fixed.
    $endgroup$
    – wgoodall01
    14 hours ago






  • 2




    $begingroup$
    Once you have made this fix, evaluate DownValues[g]; that should give a hint as to which case gets applied first. Generally, it tries to put special cases first before general ones.
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    Or just execute ?g to see the order of the definitions.
    $endgroup$
    – Roman
    12 hours ago














6












6








6





$begingroup$


If you define a function g, like so:



g[x_?EvenQ] := "even"    
g[x_?NumberQ] := "number"


why will Mathematica always return g[2] == "Even", even though NumberQ[2] == True?



More specifically, is there a defined order in which Mathematica will try to match function cases? Does it evaluate the most specific match first?










share|improve this question









New contributor




wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




If you define a function g, like so:



g[x_?EvenQ] := "even"    
g[x_?NumberQ] := "number"


why will Mathematica always return g[2] == "Even", even though NumberQ[2] == True?



More specifically, is there a defined order in which Mathematica will try to match function cases? Does it evaluate the most specific match first?







pattern-matching expression-test






share|improve this question









New contributor




wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 14 hours ago







wgoodall01













New contributor




wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 14 hours ago









wgoodall01wgoodall01

1335




1335




New contributor




wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






wgoodall01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    g[x_NumberQ] means to match arguments with the head NumberQ. What you want is to match arguments such that NumberQ[x] is True, which is g[x_?NumberQ]. Look up PatternTest[]. (Before you make this correction, make sure to run Clear[g] first.)
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    That's right---fixed.
    $endgroup$
    – wgoodall01
    14 hours ago






  • 2




    $begingroup$
    Once you have made this fix, evaluate DownValues[g]; that should give a hint as to which case gets applied first. Generally, it tries to put special cases first before general ones.
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    Or just execute ?g to see the order of the definitions.
    $endgroup$
    – Roman
    12 hours ago


















  • $begingroup$
    g[x_NumberQ] means to match arguments with the head NumberQ. What you want is to match arguments such that NumberQ[x] is True, which is g[x_?NumberQ]. Look up PatternTest[]. (Before you make this correction, make sure to run Clear[g] first.)
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    That's right---fixed.
    $endgroup$
    – wgoodall01
    14 hours ago






  • 2




    $begingroup$
    Once you have made this fix, evaluate DownValues[g]; that should give a hint as to which case gets applied first. Generally, it tries to put special cases first before general ones.
    $endgroup$
    – J. M. is computer-less
    14 hours ago












  • $begingroup$
    Or just execute ?g to see the order of the definitions.
    $endgroup$
    – Roman
    12 hours ago
















$begingroup$
g[x_NumberQ] means to match arguments with the head NumberQ. What you want is to match arguments such that NumberQ[x] is True, which is g[x_?NumberQ]. Look up PatternTest[]. (Before you make this correction, make sure to run Clear[g] first.)
$endgroup$
– J. M. is computer-less
14 hours ago






$begingroup$
g[x_NumberQ] means to match arguments with the head NumberQ. What you want is to match arguments such that NumberQ[x] is True, which is g[x_?NumberQ]. Look up PatternTest[]. (Before you make this correction, make sure to run Clear[g] first.)
$endgroup$
– J. M. is computer-less
14 hours ago














$begingroup$
That's right---fixed.
$endgroup$
– wgoodall01
14 hours ago




$begingroup$
That's right---fixed.
$endgroup$
– wgoodall01
14 hours ago




2




2




$begingroup$
Once you have made this fix, evaluate DownValues[g]; that should give a hint as to which case gets applied first. Generally, it tries to put special cases first before general ones.
$endgroup$
– J. M. is computer-less
14 hours ago






$begingroup$
Once you have made this fix, evaluate DownValues[g]; that should give a hint as to which case gets applied first. Generally, it tries to put special cases first before general ones.
$endgroup$
– J. M. is computer-less
14 hours ago














$begingroup$
Or just execute ?g to see the order of the definitions.
$endgroup$
– Roman
12 hours ago




$begingroup$
Or just execute ?g to see the order of the definitions.
$endgroup$
– Roman
12 hours ago










1 Answer
1






active

oldest

votes


















11












$begingroup$

TheOrderingOfDefinitions




  • ... The Wolfram System follows the principle of trying to put more general definitions after more specific ones. This means that special cases of rules are typically tried before more general cases.

  • Although in many practical cases, the Wolfram System can recognize when one rule is more general than another, you should realize that this is not always possible. For example, if two rules both contain complicated /; conditions, it may not be possible to work out which is more general, and, in fact, there may not be a definite ordering. Whenever the appropriate ordering is not clear, the Wolfram System stores rules in the order you give them.




ClearAll[g]
g[x_?EvenQ] := "even"
g[x_?NumberQ] := "number"
g /@ {1, 2}



{"number", "even"}




ClearAll[h]
h[x_?NumberQ] := "number"
h[x_?EvenQ] := "even"
h /@ {1, 2}



{"number", "number"}







share|improve this answer











$endgroup$













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    1 Answer
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    active

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    11












    $begingroup$

    TheOrderingOfDefinitions




    • ... The Wolfram System follows the principle of trying to put more general definitions after more specific ones. This means that special cases of rules are typically tried before more general cases.

    • Although in many practical cases, the Wolfram System can recognize when one rule is more general than another, you should realize that this is not always possible. For example, if two rules both contain complicated /; conditions, it may not be possible to work out which is more general, and, in fact, there may not be a definite ordering. Whenever the appropriate ordering is not clear, the Wolfram System stores rules in the order you give them.




    ClearAll[g]
    g[x_?EvenQ] := "even"
    g[x_?NumberQ] := "number"
    g /@ {1, 2}



    {"number", "even"}




    ClearAll[h]
    h[x_?NumberQ] := "number"
    h[x_?EvenQ] := "even"
    h /@ {1, 2}



    {"number", "number"}







    share|improve this answer











    $endgroup$


















      11












      $begingroup$

      TheOrderingOfDefinitions




      • ... The Wolfram System follows the principle of trying to put more general definitions after more specific ones. This means that special cases of rules are typically tried before more general cases.

      • Although in many practical cases, the Wolfram System can recognize when one rule is more general than another, you should realize that this is not always possible. For example, if two rules both contain complicated /; conditions, it may not be possible to work out which is more general, and, in fact, there may not be a definite ordering. Whenever the appropriate ordering is not clear, the Wolfram System stores rules in the order you give them.




      ClearAll[g]
      g[x_?EvenQ] := "even"
      g[x_?NumberQ] := "number"
      g /@ {1, 2}



      {"number", "even"}




      ClearAll[h]
      h[x_?NumberQ] := "number"
      h[x_?EvenQ] := "even"
      h /@ {1, 2}



      {"number", "number"}







      share|improve this answer











      $endgroup$
















        11












        11








        11





        $begingroup$

        TheOrderingOfDefinitions




        • ... The Wolfram System follows the principle of trying to put more general definitions after more specific ones. This means that special cases of rules are typically tried before more general cases.

        • Although in many practical cases, the Wolfram System can recognize when one rule is more general than another, you should realize that this is not always possible. For example, if two rules both contain complicated /; conditions, it may not be possible to work out which is more general, and, in fact, there may not be a definite ordering. Whenever the appropriate ordering is not clear, the Wolfram System stores rules in the order you give them.




        ClearAll[g]
        g[x_?EvenQ] := "even"
        g[x_?NumberQ] := "number"
        g /@ {1, 2}



        {"number", "even"}




        ClearAll[h]
        h[x_?NumberQ] := "number"
        h[x_?EvenQ] := "even"
        h /@ {1, 2}



        {"number", "number"}







        share|improve this answer











        $endgroup$



        TheOrderingOfDefinitions




        • ... The Wolfram System follows the principle of trying to put more general definitions after more specific ones. This means that special cases of rules are typically tried before more general cases.

        • Although in many practical cases, the Wolfram System can recognize when one rule is more general than another, you should realize that this is not always possible. For example, if two rules both contain complicated /; conditions, it may not be possible to work out which is more general, and, in fact, there may not be a definite ordering. Whenever the appropriate ordering is not clear, the Wolfram System stores rules in the order you give them.




        ClearAll[g]
        g[x_?EvenQ] := "even"
        g[x_?NumberQ] := "number"
        g /@ {1, 2}



        {"number", "even"}




        ClearAll[h]
        h[x_?NumberQ] := "number"
        h[x_?EvenQ] := "even"
        h /@ {1, 2}



        {"number", "number"}








        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 14 hours ago

























        answered 14 hours ago









        kglrkglr

        186k10203422




        186k10203422






















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