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Why does a metal block make a shrill sound but not a wooden block upon hammering?

How does paper make sound when it is torn?Why do cold metal plate make less noise?Does sound absorption depends upon the amplitude of sound wave?Why does medium not affect the frequency of sound?Undamped oscillations of sound waveWhat is the shape of the vibration when the system is exited at off natural/resonant frequency?A metallic container when hammered deforms but a wine glass when falls or hammered breaks. Why?Why is sound produced when we hit a metal?Why does fire make very little sound?At what frequency does a string vibrate?

1

1

$begingroup$

When hammered, a metal block makes a shrill sound but not a wooden block of identical shape. Is it that the wooden block vibrates with lesser frequency than the metal block? If so, why is that? Also why is the vibration of a metallic block more visible than a wooden block? More amplitude?

solid-state-physics acoustics everyday-life elasticity vibrations

share|cite|improve this question

edited 2 hours ago

mithusengupta123

asked 2 hours ago

mithusengupta123mithusengupta123

1,24211435

$endgroup$

add a comment | 

1

1

$begingroup$

When hammered, a metal block makes a shrill sound but not a wooden block of identical shape. Is it that the wooden block vibrates with lesser frequency than the metal block? If so, why is that? Also why is the vibration of a metallic block more visible than a wooden block? More amplitude?

solid-state-physics acoustics everyday-life elasticity vibrations

share|cite|improve this question

edited 2 hours ago

mithusengupta123

asked 2 hours ago

mithusengupta123mithusengupta123

1,24211435

$endgroup$

add a comment | 

$begingroup$

When hammered, a metal block makes a shrill sound but not a wooden block of identical shape. Is it that the wooden block vibrates with lesser frequency than the metal block? If so, why is that? Also why is the vibration of a metallic block more visible than a wooden block? More amplitude?

solid-state-physics acoustics everyday-life elasticity vibrations

share|cite|improve this question

edited 2 hours ago

mithusengupta123

asked 2 hours ago

mithusengupta123mithusengupta123

1,24211435

$endgroup$

share|cite|improve this question

edited 2 hours ago

mithusengupta123

asked 2 hours ago

mithusengupta123mithusengupta123

1,24211435

share|cite|improve this question

edited 2 hours ago

mithusengupta123

asked 2 hours ago

mithusengupta123mithusengupta123

1,24211435

asked 2 hours ago

mithusengupta123mithusengupta123

1,24211435

asked 2 hours ago

mithusengupta123mithusengupta123

1,24211435

2 Answers
2

active

oldest

votes

3

$begingroup$

Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?

'Yes', to the first question.

Metal is stiffer than wood and produces higher frequencies (higher pitch).

This follows from the wave equation (here in one dimension):

$$u_{tt}=frac{E}{rho}u_{xx}$$

$E$ is Young's Modulus and $rho$ the material's density.

When solved, the solution contains a time-dependent term like this:

$$cosBig(frac{npi ct}{L}Big)$$

where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).

To find the frequencies:

$$cos omega t=cosBig(frac{npi ct}{L}Big)$$

$$omega=2pi f=frac{npi c}{L}$$

$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$

The fundamental frequency (for $n=1$) is given by:

$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$

So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.

share|cite|improve this answer

edited 1 hour ago

answered 1 hour ago

GertGert

17.8k32959

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
  $endgroup$
  – mithusengupta123
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
  $endgroup$
  – Gert
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
  $endgroup$
  – mithusengupta123
  34 mins ago
  

  
  
  
  

add a comment | 

2

$begingroup$

The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).

So the wooden block will vibrate with lower frequencies and also with lower amplitude (and also with lower duration).

share|cite|improve this answer

answered 49 mins ago

user45664user45664

1,0782824

$endgroup$

add a comment | 

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3

$begingroup$

Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?

'Yes', to the first question.

Metal is stiffer than wood and produces higher frequencies (higher pitch).

This follows from the wave equation (here in one dimension):

$$u_{tt}=frac{E}{rho}u_{xx}$$

$E$ is Young's Modulus and $rho$ the material's density.

When solved, the solution contains a time-dependent term like this:

$$cosBig(frac{npi ct}{L}Big)$$

where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).

To find the frequencies:

$$cos omega t=cosBig(frac{npi ct}{L}Big)$$

$$omega=2pi f=frac{npi c}{L}$$

$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$

The fundamental frequency (for $n=1$) is given by:

$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$

So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.

share|cite|improve this answer

edited 1 hour ago

answered 1 hour ago

GertGert

17.8k32959

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
  $endgroup$
  – mithusengupta123
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
  $endgroup$
  – Gert
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
  $endgroup$
  – mithusengupta123
  34 mins ago
  

  
  
  
  

add a comment | 

3

$begingroup$

Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?

'Yes', to the first question.

Metal is stiffer than wood and produces higher frequencies (higher pitch).

This follows from the wave equation (here in one dimension):

$$u_{tt}=frac{E}{rho}u_{xx}$$

$E$ is Young's Modulus and $rho$ the material's density.

When solved, the solution contains a time-dependent term like this:

$$cosBig(frac{npi ct}{L}Big)$$

where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).

To find the frequencies:

$$cos omega t=cosBig(frac{npi ct}{L}Big)$$

$$omega=2pi f=frac{npi c}{L}$$

$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$

The fundamental frequency (for $n=1$) is given by:

$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$

So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.

share|cite|improve this answer

edited 1 hour ago

answered 1 hour ago

GertGert

17.8k32959

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
  $endgroup$
  – mithusengupta123
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
  $endgroup$
  – Gert
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
  $endgroup$
  – mithusengupta123
  34 mins ago
  

  
  
  
  

add a comment | 

$begingroup$

Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?

'Yes', to the first question.

Metal is stiffer than wood and produces higher frequencies (higher pitch).

This follows from the wave equation (here in one dimension):

$$u_{tt}=frac{E}{rho}u_{xx}$$

$E$ is Young's Modulus and $rho$ the material's density.

When solved, the solution contains a time-dependent term like this:

$$cosBig(frac{npi ct}{L}Big)$$

where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).

To find the frequencies:

$$cos omega t=cosBig(frac{npi ct}{L}Big)$$

$$omega=2pi f=frac{npi c}{L}$$

$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$

The fundamental frequency (for $n=1$) is given by:

$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$

So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.

share|cite|improve this answer

edited 1 hour ago

answered 1 hour ago

GertGert

17.8k32959

$endgroup$

share|cite|improve this answer

edited 1 hour ago

answered 1 hour ago

GertGert

17.8k32959

answered 1 hour ago

GertGert

17.8k32959

answered 1 hour ago

GertGert

17.8k32959

2

$begingroup$

The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).

So the wooden block will vibrate with lower frequencies and also with lower amplitude (and also with lower duration).

share|cite|improve this answer

answered 49 mins ago

user45664user45664

1,0782824

$endgroup$

add a comment | 

2

$begingroup$

The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).

So the wooden block will vibrate with lower frequencies and also with lower amplitude (and also with lower duration).

share|cite|improve this answer

answered 49 mins ago

user45664user45664

1,0782824

$endgroup$

add a comment | 

$begingroup$

The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).

So the wooden block will vibrate with lower frequencies and also with lower amplitude (and also with lower duration).

share|cite|improve this answer

answered 49 mins ago

user45664user45664

1,0782824

$endgroup$

share|cite|improve this answer

answered 49 mins ago

user45664user45664

1,0782824

answered 49 mins ago

user45664user45664

1,0782824

answered 49 mins ago

user45664user45664

1,0782824