Replacement expressionsExtracting equations from Piecewise expressionsComparing Mathematica expressions like...
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Replacement expressions
Extracting equations from Piecewise expressionsComparing Mathematica expressions like diffSimplifying expressions involving SumPatterns of function-arguments in expressionsSelectively converting numerical strings to expressionsSimplify binary expressionsHow to I convert the following into a list of numbers?Handling long expressionsExpression replacement with variable exponentsDo replacement only on certain specific forms
$begingroup$
I have the following expressions:
R[1, 1] R[2, 1] R[3, 1] R[4, 1]
sum[FF[3, ak[1] - ak[2], 1], EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]]
By what procedure can I convert such expressions into expression:
sum[R[1, 1], FF[3, ak[2] - ak[2], 1], R[2, 1] , EE[2, ak[2] - ak[3], 0], R[3, 1] , EE[2, ak[3] - ak[4], 0] , R[4, 1]]
list-manipulation expression-manipulation
New contributor
$endgroup$
add a comment |
$begingroup$
I have the following expressions:
R[1, 1] R[2, 1] R[3, 1] R[4, 1]
sum[FF[3, ak[1] - ak[2], 1], EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]]
By what procedure can I convert such expressions into expression:
sum[R[1, 1], FF[3, ak[2] - ak[2], 1], R[2, 1] , EE[2, ak[2] - ak[3], 0], R[3, 1] , EE[2, ak[3] - ak[4], 0] , R[4, 1]]
list-manipulation expression-manipulation
New contributor
$endgroup$
$begingroup$
Perhaps you should look atRiffle
.
$endgroup$
– m_goldberg
1 hour ago
add a comment |
$begingroup$
I have the following expressions:
R[1, 1] R[2, 1] R[3, 1] R[4, 1]
sum[FF[3, ak[1] - ak[2], 1], EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]]
By what procedure can I convert such expressions into expression:
sum[R[1, 1], FF[3, ak[2] - ak[2], 1], R[2, 1] , EE[2, ak[2] - ak[3], 0], R[3, 1] , EE[2, ak[3] - ak[4], 0] , R[4, 1]]
list-manipulation expression-manipulation
New contributor
$endgroup$
I have the following expressions:
R[1, 1] R[2, 1] R[3, 1] R[4, 1]
sum[FF[3, ak[1] - ak[2], 1], EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]]
By what procedure can I convert such expressions into expression:
sum[R[1, 1], FF[3, ak[2] - ak[2], 1], R[2, 1] , EE[2, ak[2] - ak[3], 0], R[3, 1] , EE[2, ak[3] - ak[4], 0] , R[4, 1]]
list-manipulation expression-manipulation
list-manipulation expression-manipulation
New contributor
New contributor
edited 1 hour ago
m_goldberg
86.8k872197
86.8k872197
New contributor
asked 2 hours ago
Piotr DrygaśPiotr Drygaś
161
161
New contributor
New contributor
$begingroup$
Perhaps you should look atRiffle
.
$endgroup$
– m_goldberg
1 hour ago
add a comment |
$begingroup$
Perhaps you should look atRiffle
.
$endgroup$
– m_goldberg
1 hour ago
$begingroup$
Perhaps you should look at
Riffle
.$endgroup$
– m_goldberg
1 hour ago
$begingroup$
Perhaps you should look at
Riffle
.$endgroup$
– m_goldberg
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
expr = R[1, 1] R[2, 1] R[3, 1] R[4, 1] sum[FF[3, ak[1] - ak[2], 1],
EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]];
expr /. a_ sum[b__] :> sum @@ Riffle[List @@ a, {b}]
sum[R[1, 1], FF[3, ak[1] - ak[2], 1], R[2, 1],
EE[2, ak[2] - ak[3], 0], R[3, 1], EE[2, ak[3] - ak[4], 0], R[4, 1]]
$endgroup$
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
expr = R[1, 1] R[2, 1] R[3, 1] R[4, 1] sum[FF[3, ak[1] - ak[2], 1],
EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]];
expr /. a_ sum[b__] :> sum @@ Riffle[List @@ a, {b}]
sum[R[1, 1], FF[3, ak[1] - ak[2], 1], R[2, 1],
EE[2, ak[2] - ak[3], 0], R[3, 1], EE[2, ak[3] - ak[4], 0], R[4, 1]]
$endgroup$
add a comment |
$begingroup$
expr = R[1, 1] R[2, 1] R[3, 1] R[4, 1] sum[FF[3, ak[1] - ak[2], 1],
EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]];
expr /. a_ sum[b__] :> sum @@ Riffle[List @@ a, {b}]
sum[R[1, 1], FF[3, ak[1] - ak[2], 1], R[2, 1],
EE[2, ak[2] - ak[3], 0], R[3, 1], EE[2, ak[3] - ak[4], 0], R[4, 1]]
$endgroup$
add a comment |
$begingroup$
expr = R[1, 1] R[2, 1] R[3, 1] R[4, 1] sum[FF[3, ak[1] - ak[2], 1],
EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]];
expr /. a_ sum[b__] :> sum @@ Riffle[List @@ a, {b}]
sum[R[1, 1], FF[3, ak[1] - ak[2], 1], R[2, 1],
EE[2, ak[2] - ak[3], 0], R[3, 1], EE[2, ak[3] - ak[4], 0], R[4, 1]]
$endgroup$
expr = R[1, 1] R[2, 1] R[3, 1] R[4, 1] sum[FF[3, ak[1] - ak[2], 1],
EE[2, ak[2] - ak[3], 0], EE[2, ak[3] - ak[4], 0]];
expr /. a_ sum[b__] :> sum @@ Riffle[List @@ a, {b}]
sum[R[1, 1], FF[3, ak[1] - ak[2], 1], R[2, 1],
EE[2, ak[2] - ak[3], 0], R[3, 1], EE[2, ak[3] - ak[4], 0], R[4, 1]]
answered 2 hours ago
kglrkglr
186k10203422
186k10203422
add a comment |
add a comment |
Piotr Drygaś is a new contributor. Be nice, and check out our Code of Conduct.
Piotr Drygaś is a new contributor. Be nice, and check out our Code of Conduct.
Piotr Drygaś is a new contributor. Be nice, and check out our Code of Conduct.
Piotr Drygaś is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Perhaps you should look at
Riffle
.$endgroup$
– m_goldberg
1 hour ago