Increment each digit in a number to form a new numberDisplaying each number of an integer in a sequenceUgly...
What is the data structure of $@ in shell?
How can a large fleets maintain formation in interstellar space?
Why is Agricola named as such?
How to use Mathematica to do a complex integrate with poles in real axis?
In Linux what happens if 1000 files in a directory are moved to another location while another 300 files were added to the source directory?
Avoid page break between paragraphs
Why did the villain in the first Men in Black movie care about Earth's Cockroaches?
False written accusations not made public - is there law to cover this?
How do I append a character to the end of every line in an Excel cell?
Graph with overlapping labels
Variable is not visible
Does dispel magic end a master's control over their undead?
It took me a lot of time to make this, pls like. (YouTube Comments #1)
Does every functor from Set to Set preserve products?
Why did Democrats in the Senate oppose the Born-Alive Abortion Survivors Protection Act (2019 S.130)?
What to look for when criticizing poetry?
If I delete my router's history can my ISP still provide it to my parents?
How should I handle players who ignore the session zero agreement?
Crontab: Ubuntu running script (noob)
Alien invasion to probe us, why?
Citing paywalled articles accessed via illegal web sharing
A Missing Symbol for This Logo
Words and Words with "ver-" Prefix
Increment each digit in a number to form a new number
Increment each digit in a number to form a new number
Displaying each number of an integer in a sequenceUgly Numbers: A Rags-to-Riches StoryProject Euler # 22: Names scoresProject Euler 25 - x-digit Fibonacci NumberProject Euler #49 Prime permutationsScrabble Tile CounterHackerrank: Lucky Number Eight (Dynamic Programming)HackerRank week of code 32 competition: GeometrickTrickGoogle Foobar level 3BalancedPassword Codility task
$begingroup$
Today I've found /r/dailyprogrammer and I've solved an easy challenge. I'm new to coding and I'm not sure if this is good way to solve this kind of problems. Could you, please, give me some hints? How to make my code more clear and readable? Thanks!
Challange description:
A number is input in computer then a new no should get printed by
adding one to each of its digit. If you encounter a 9, insert a 10
(don't carry over, just shift things around).
For example, 998 becomes 10109.
Bonus
This challenge is trivial to do if you map it to a string to iterate
over the input, operate, and then cast it back. Instead, try doing it
without casting it as a string at any point, keep it numeric (int,
float if you need it) only.
private static int Challange(int number)
{
int digits = (int)Math.Log10(number); //this is number of digits -1
int result = 0;
for (int i=0; i <= digits; i++)
{
int tens = (int)(Math.Pow(10, digits - i));
int currentDigit = ((number / tens) % 10);
if (currentDigit == 9) result *= 10;
result += (currentDigit + 1) * tens;
}
return result;
}
c# programming-challenge
New contributor
$endgroup$
add a comment |
$begingroup$
Today I've found /r/dailyprogrammer and I've solved an easy challenge. I'm new to coding and I'm not sure if this is good way to solve this kind of problems. Could you, please, give me some hints? How to make my code more clear and readable? Thanks!
Challange description:
A number is input in computer then a new no should get printed by
adding one to each of its digit. If you encounter a 9, insert a 10
(don't carry over, just shift things around).
For example, 998 becomes 10109.
Bonus
This challenge is trivial to do if you map it to a string to iterate
over the input, operate, and then cast it back. Instead, try doing it
without casting it as a string at any point, keep it numeric (int,
float if you need it) only.
private static int Challange(int number)
{
int digits = (int)Math.Log10(number); //this is number of digits -1
int result = 0;
for (int i=0; i <= digits; i++)
{
int tens = (int)(Math.Pow(10, digits - i));
int currentDigit = ((number / tens) % 10);
if (currentDigit == 9) result *= 10;
result += (currentDigit + 1) * tens;
}
return result;
}
c# programming-challenge
New contributor
$endgroup$
add a comment |
$begingroup$
Today I've found /r/dailyprogrammer and I've solved an easy challenge. I'm new to coding and I'm not sure if this is good way to solve this kind of problems. Could you, please, give me some hints? How to make my code more clear and readable? Thanks!
Challange description:
A number is input in computer then a new no should get printed by
adding one to each of its digit. If you encounter a 9, insert a 10
(don't carry over, just shift things around).
For example, 998 becomes 10109.
Bonus
This challenge is trivial to do if you map it to a string to iterate
over the input, operate, and then cast it back. Instead, try doing it
without casting it as a string at any point, keep it numeric (int,
float if you need it) only.
private static int Challange(int number)
{
int digits = (int)Math.Log10(number); //this is number of digits -1
int result = 0;
for (int i=0; i <= digits; i++)
{
int tens = (int)(Math.Pow(10, digits - i));
int currentDigit = ((number / tens) % 10);
if (currentDigit == 9) result *= 10;
result += (currentDigit + 1) * tens;
}
return result;
}
c# programming-challenge
New contributor
$endgroup$
Today I've found /r/dailyprogrammer and I've solved an easy challenge. I'm new to coding and I'm not sure if this is good way to solve this kind of problems. Could you, please, give me some hints? How to make my code more clear and readable? Thanks!
Challange description:
A number is input in computer then a new no should get printed by
adding one to each of its digit. If you encounter a 9, insert a 10
(don't carry over, just shift things around).
For example, 998 becomes 10109.
Bonus
This challenge is trivial to do if you map it to a string to iterate
over the input, operate, and then cast it back. Instead, try doing it
without casting it as a string at any point, keep it numeric (int,
float if you need it) only.
private static int Challange(int number)
{
int digits = (int)Math.Log10(number); //this is number of digits -1
int result = 0;
for (int i=0; i <= digits; i++)
{
int tens = (int)(Math.Pow(10, digits - i));
int currentDigit = ((number / tens) % 10);
if (currentDigit == 9) result *= 10;
result += (currentDigit + 1) * tens;
}
return result;
}
c# programming-challenge
c# programming-challenge
New contributor
New contributor
edited 2 hours ago
t3chb0t
34.7k750121
34.7k750121
New contributor
asked 2 hours ago
nowakasdnowakasd
162
162
New contributor
New contributor
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
It works, but it's a bit tricky to follow the logic and work out why. If you work from the other end then you can avoid the Log
and Pow
and shifting the partial result, and I find that easier to read.
Challange
is not a descriptive name. What does the method do? IncrementDigits
might be a better name, for example.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "196"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
nowakasd is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f214403%2fincrement-each-digit-in-a-number-to-form-a-new-number%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
It works, but it's a bit tricky to follow the logic and work out why. If you work from the other end then you can avoid the Log
and Pow
and shifting the partial result, and I find that easier to read.
Challange
is not a descriptive name. What does the method do? IncrementDigits
might be a better name, for example.
$endgroup$
add a comment |
$begingroup$
It works, but it's a bit tricky to follow the logic and work out why. If you work from the other end then you can avoid the Log
and Pow
and shifting the partial result, and I find that easier to read.
Challange
is not a descriptive name. What does the method do? IncrementDigits
might be a better name, for example.
$endgroup$
add a comment |
$begingroup$
It works, but it's a bit tricky to follow the logic and work out why. If you work from the other end then you can avoid the Log
and Pow
and shifting the partial result, and I find that easier to read.
Challange
is not a descriptive name. What does the method do? IncrementDigits
might be a better name, for example.
$endgroup$
It works, but it's a bit tricky to follow the logic and work out why. If you work from the other end then you can avoid the Log
and Pow
and shifting the partial result, and I find that easier to read.
Challange
is not a descriptive name. What does the method do? IncrementDigits
might be a better name, for example.
answered 2 hours ago
Peter TaylorPeter Taylor
17.4k2862
17.4k2862
add a comment |
add a comment |
nowakasd is a new contributor. Be nice, and check out our Code of Conduct.
nowakasd is a new contributor. Be nice, and check out our Code of Conduct.
nowakasd is a new contributor. Be nice, and check out our Code of Conduct.
nowakasd is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f214403%2fincrement-each-digit-in-a-number-to-form-a-new-number%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown