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Equation with several exponents


How can I get the exact solution of this equation (inequality equation)?Solve symbolically a transcendental trigonometric equation and plot its solutionsCan't solve equation having complex coefficientsIs there a change in V10 with Solve and exponents?Problem with Solve for simple equationSolving Diophantine equation with conditions using MathematicaApproximating an equation to an integerSolve an equation with LaplacianHow to solve a complex valued equation?Solve matrix equation













3












$begingroup$


Is there a way to get the result for this value of x?



x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2])


I've tried Solve, FindInstance and I did not get a solution



I tried this:



Solve[x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2]),{x}]





equation-solving







share|improve this question









$endgroup$

















    3












    $begingroup$


    Is there a way to get the result for this value of x?



    x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2])


    I've tried Solve, FindInstance and I did not get a solution



    I tried this:



    Solve[x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2]),{x}]





    equation-solving







    share|improve this question









    $endgroup$















      3












      3








      3





      $begingroup$


      Is there a way to get the result for this value of x?



      x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2])


      I've tried Solve, FindInstance and I did not get a solution



      I tried this:



      Solve[x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2]),{x}]





      equation-solving







      share|improve this question









      $endgroup$




      Is there a way to get the result for this value of x?



      x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2])


      I've tried Solve, FindInstance and I did not get a solution



      I tried this:



      Solve[x^x^(x^(1/6)/6)==Sqrt[2^9]^(2*Sqrt[2])^(2/3+2*Sqrt[2]),{x}]





      equation-solving




      equation-solving






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 hours ago









      LCarvalhoLCarvalho

      5,77642986




      5,77642986






















          1 Answer
          1






          active

          oldest

          votes


















          3












          $begingroup$

          Try



          NSolve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals]
          
(*{x->512}*)





          share|improve this answer









          $endgroup$













          • $begingroup$
            Little detail that makes all the difference. Thanks a lot!!!
            $endgroup$
            – LCarvalho
            2 hours ago








          • 2




            $begingroup$
            Solve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals] also works!
            $endgroup$
            – Ulrich Neumann
            2 hours ago











          Your Answer





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          1 Answer
          1






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          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3












          $begingroup$

          Try



          NSolve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals]
          
(*{x->512}*)





          share|improve this answer









          $endgroup$













          • $begingroup$
            Little detail that makes all the difference. Thanks a lot!!!
            $endgroup$
            – LCarvalho
            2 hours ago








          • 2




            $begingroup$
            Solve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals] also works!
            $endgroup$
            – Ulrich Neumann
            2 hours ago
















          3












          $begingroup$

          Try



          NSolve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals]
          
(*{x->512}*)





          share|improve this answer









          $endgroup$













          • $begingroup$
            Little detail that makes all the difference. Thanks a lot!!!
            $endgroup$
            – LCarvalho
            2 hours ago








          • 2




            $begingroup$
            Solve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals] also works!
            $endgroup$
            – Ulrich Neumann
            2 hours ago














          3












          3








          3





          $begingroup$

          Try



          NSolve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals]
          
(*{x->512}*)





          share|improve this answer









          $endgroup$



          Try



          NSolve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals]
          
(*{x->512}*)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 hours ago









          Ulrich NeumannUlrich Neumann

          9,151516




          9,151516












          • $begingroup$
            Little detail that makes all the difference. Thanks a lot!!!
            $endgroup$
            – LCarvalho
            2 hours ago








          • 2




            $begingroup$
            Solve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals] also works!
            $endgroup$
            – Ulrich Neumann
            2 hours ago


















          • $begingroup$
            Little detail that makes all the difference. Thanks a lot!!!
            $endgroup$
            – LCarvalho
            2 hours ago








          • 2




            $begingroup$
            Solve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals] also works!
            $endgroup$
            – Ulrich Neumann
            2 hours ago
















          $begingroup$
          Little detail that makes all the difference. Thanks a lot!!!
          $endgroup$
          – LCarvalho
          2 hours ago






          $begingroup$
          Little detail that makes all the difference. Thanks a lot!!!
          $endgroup$
          – LCarvalho
          2 hours ago






          2




          2




          $begingroup$
          Solve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals] also works!
          $endgroup$
          – Ulrich Neumann
          2 hours ago




          $begingroup$
          Solve[x^x^(x^(1/6)/6) == Sqrt[2^9]^(2*Sqrt[2])^(2/3 + 2*Sqrt[2]), x, Reals] also works!
          $endgroup$
          – Ulrich Neumann
          2 hours ago


















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