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How to pivot a dataframe with two columns with no index
How to merge two dictionaries in a single expression?How do I check whether a file exists without exceptions?Finding the index of an item given a list containing it in PythonAccessing the index in 'for' loops?Add one row to pandas DataFrameAdding new column to existing DataFrame in Python pandas“Large data” work flows using pandasChange data type of columns in PandasSelect rows from a DataFrame based on values in a column in pandasHow to pivot a dataframe
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
asked 5 hours ago
macyyy33macyyy33
385
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
asked 5 hours ago
macyyy33macyyy33
385
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
asked 5 hours ago
macyyy33macyyy33
385
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
python pandas
asked 5 hours ago
macyyy33macyyy33
385
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
macyyy33macyyy33
385
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 5 hours ago
macyyy33
asked 5 hours ago
macyyy33macyyy33
385
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
macyyy33macyyy33
385
asked 5 hours ago
macyyy33macyyy33
385
385
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
macyyy33 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
You can usea.Tfor short.
– Scott Boston
5 hours ago
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered 4 hours ago
ALollzALollz
14.2k31636
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
add a comment |
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
add a comment |
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
answered 4 hours ago
Scott BostonScott Boston
55.8k73156
55.8k73156
add a comment |
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
You can usea.Tfor short.
– Scott Boston
5 hours ago
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
You can usea.Tfor short.
– Scott Boston
5 hours ago
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
answered 5 hours ago
Niklas MertschNiklas Mertsch
473115
473115
You can usea.Tfor short.
– Scott Boston
5 hours ago
add a comment |
You can usea.Tfor short.
– Scott Boston
5 hours ago
You can use
a.T for short.– Scott Boston
5 hours ago
You can use
a.T for short.– Scott Boston
5 hours ago
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered 4 hours ago
ALollzALollz
14.2k31636
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered 4 hours ago
ALollzALollz
14.2k31636
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered 4 hours ago
ALollzALollz
14.2k31636
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered 4 hours ago
ALollzALollz
14.2k31636
answered 4 hours ago
ALollzALollz
14.2k31636
answered 4 hours ago
ALollzALollz
14.2k31636
answered 4 hours ago
ALollzALollz
14.2k31636
14.2k31636
add a comment |
add a comment |
macyyy33 is a new contributor. Be nice, and check out our Code of Conduct.
macyyy33 is a new contributor. Be nice, and check out our Code of Conduct.
macyyy33 is a new contributor. Be nice, and check out our Code of Conduct.
macyyy33 is a new contributor. Be nice, and check out our Code of Conduct.
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