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Transpose a matrix and parenthesis

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Transpose a matrix and parenthesis

What is the difference between empty and @empty?Redefine marginpar with renewcommandRead command with varying input argumentsAsymetric behaviour in user command with conditionalsName separators, if condition for same commandnewcommand with optional multi-line argument and implicit itemize environmentDefining a command that scans every arguments' macro “looking for” a tokenUsing fully expanded result as a simple string (with citet and IfSubStr)Define a new command with parameters inside newcommandHow to avoid using curly braces when placing a DeclareMathOperator command in subscript or superscript, while preserving spacing?

1

I would like to define a command transp having eventually one argument : the name of the matrix and finally two outputs.

1. 
   transp{A} is the matrix A^T between parenthesis,


2. 
   transp A is just the matrix A^T.

I tried this command :

newcommand{transp}[1]{

ifstrempty{#1}{{}^{text{tbf{T}}} }{{}^{text{tbf{T}}} left( #1 right)}}

but to print the transpose symbol I have to write transp{}. Can I modify the previous command in order to just write transp (as mentioned in 2.) ?

macros conditionals math-operators

share|improve this question

asked 1 hour ago

jowe_19jowe_19

6510

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Usually foo A and foo{A} are the same for a macro foo taking an argument. So this is not easily done and would go against the normal behaviour (I don't want to say good practice, because I'm led to believe that it would be better practice to use braces even for one-token arguments). I think I saw a related question a while ago, but I can't find it now and it might have been about something else entirely.
  
  – moewe
  1 hour ago
  
  
  

  
  
  
  

add a comment | 

1

I would like to define a command transp having eventually one argument : the name of the matrix and finally two outputs.

1. 
   transp{A} is the matrix A^T between parenthesis,


2. 
   transp A is just the matrix A^T.

I tried this command :

newcommand{transp}[1]{

ifstrempty{#1}{{}^{text{tbf{T}}} }{{}^{text{tbf{T}}} left( #1 right)}}

but to print the transpose symbol I have to write transp{}. Can I modify the previous command in order to just write transp (as mentioned in 2.) ?

macros conditionals math-operators

share|improve this question

asked 1 hour ago

jowe_19jowe_19

6510

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Usually foo A and foo{A} are the same for a macro foo taking an argument. So this is not easily done and would go against the normal behaviour (I don't want to say good practice, because I'm led to believe that it would be better practice to use braces even for one-token arguments). I think I saw a related question a while ago, but I can't find it now and it might have been about something else entirely.
  
  – moewe
  1 hour ago
  
  
  

  
  
  
  

add a comment | 

I would like to define a command transp having eventually one argument : the name of the matrix and finally two outputs.

1. 
   transp{A} is the matrix A^T between parenthesis,


2. 
   transp A is just the matrix A^T.

I tried this command :

newcommand{transp}[1]{

ifstrempty{#1}{{}^{text{tbf{T}}} }{{}^{text{tbf{T}}} left( #1 right)}}

but to print the transpose symbol I have to write transp{}. Can I modify the previous command in order to just write transp (as mentioned in 2.) ?

macros conditionals math-operators

share|improve this question

asked 1 hour ago

jowe_19jowe_19

6510

newcommand{transp}[1]{

ifstrempty{#1}{{}^{text{tbf{T}}} }{{}^{text{tbf{T}}} left( #1 right)}}

share|improve this question

asked 1 hour ago

jowe_19jowe_19

6510

share|improve this question

asked 1 hour ago

jowe_19jowe_19

6510

asked 1 hour ago

jowe_19jowe_19

6510

asked 1 hour ago

jowe_19jowe_19

6510

2 Answers
2

active

oldest

votes

4

According to the standard TeX syntax, transp{A} and transp A are completely equivalent.

You might do in the following way:

documentclass{article}

usepackage{amsmath}



makeatletter

DeclareRobustCommand{transp}{%

  @ifnextcharbgrouptransp@parentransp@simple

}

newcommand{transp@paren}[1]{(#1)^{T}}

newcommand{transp@simple}[1]{#1^{T}}

makeatother



begin{document}



$transp A+transp{B+C}$



end{document}

but I would avoid it, because it's confusing.

I find the following much better. You explicitly mark where you want parentheses by adding *.

documentclass{article}

usepackage{amsmath}

usepackage{xparse}



NewDocumentCommand{transp}{sm}{%

  IfBooleanTF{#1}{(#2)^{T}}{#2^{T}}%

}



begin{document}



$transp{A}+transp*{B+C}$



end{document}

share|improve this answer

answered 1 hour ago

egregegreg

723k8719163219

add a comment | 

3

The following seems to work, but I doubt it is a good idea in general. Usually foo A and foo {A} give the same result for macros with one argument and the braces are needed in case the argument consists of more than one token. Indeed I would say that it is good practice to use braces for mandatory arguments even if they enclose only one token.

Note that transp without braces can only accept one token as its argument, so transp A+B is transp A and +B. In particular then, transp mathbf{A} dies horribly.

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifnextcharbgroup

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp A \

    transp{A}

  end{align*}

end{document}

A starred variant would be more common (see also egreg's answer)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifstar

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp*{A}

  end{align*}

end{document}

but you could also use an optional argument (p for parentheses, b for brackets)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand{transp}[2][]{%

  if#1p

    (#2)

  else

    if#1b

      [A]

    else

     A

    fi

  fi^{T}

}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp[b]{A}

  end{align*}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

moewemoewe

92.2k10115348

add a comment | 

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4

According to the standard TeX syntax, transp{A} and transp A are completely equivalent.

You might do in the following way:

documentclass{article}

usepackage{amsmath}



makeatletter

DeclareRobustCommand{transp}{%

  @ifnextcharbgrouptransp@parentransp@simple

}

newcommand{transp@paren}[1]{(#1)^{T}}

newcommand{transp@simple}[1]{#1^{T}}

makeatother



begin{document}



$transp A+transp{B+C}$



end{document}

but I would avoid it, because it's confusing.

I find the following much better. You explicitly mark where you want parentheses by adding *.

documentclass{article}

usepackage{amsmath}

usepackage{xparse}



NewDocumentCommand{transp}{sm}{%

  IfBooleanTF{#1}{(#2)^{T}}{#2^{T}}%

}



begin{document}



$transp{A}+transp*{B+C}$



end{document}

share|improve this answer

answered 1 hour ago

egregegreg

723k8719163219

add a comment | 

4

According to the standard TeX syntax, transp{A} and transp A are completely equivalent.

You might do in the following way:

documentclass{article}

usepackage{amsmath}



makeatletter

DeclareRobustCommand{transp}{%

  @ifnextcharbgrouptransp@parentransp@simple

}

newcommand{transp@paren}[1]{(#1)^{T}}

newcommand{transp@simple}[1]{#1^{T}}

makeatother



begin{document}



$transp A+transp{B+C}$



end{document}

but I would avoid it, because it's confusing.

I find the following much better. You explicitly mark where you want parentheses by adding *.

documentclass{article}

usepackage{amsmath}

usepackage{xparse}



NewDocumentCommand{transp}{sm}{%

  IfBooleanTF{#1}{(#2)^{T}}{#2^{T}}%

}



begin{document}



$transp{A}+transp*{B+C}$



end{document}

share|improve this answer

answered 1 hour ago

egregegreg

723k8719163219

add a comment | 

According to the standard TeX syntax, transp{A} and transp A are completely equivalent.

You might do in the following way:

documentclass{article}

usepackage{amsmath}



makeatletter

DeclareRobustCommand{transp}{%

  @ifnextcharbgrouptransp@parentransp@simple

}

newcommand{transp@paren}[1]{(#1)^{T}}

newcommand{transp@simple}[1]{#1^{T}}

makeatother



begin{document}



$transp A+transp{B+C}$



end{document}

but I would avoid it, because it's confusing.

I find the following much better. You explicitly mark where you want parentheses by adding *.

documentclass{article}

usepackage{amsmath}

usepackage{xparse}



NewDocumentCommand{transp}{sm}{%

  IfBooleanTF{#1}{(#2)^{T}}{#2^{T}}%

}



begin{document}



$transp{A}+transp*{B+C}$



end{document}

share|improve this answer

answered 1 hour ago

egregegreg

723k8719163219

documentclass{article}

usepackage{amsmath}



makeatletter

DeclareRobustCommand{transp}{%

  @ifnextcharbgrouptransp@parentransp@simple

}

newcommand{transp@paren}[1]{(#1)^{T}}

newcommand{transp@simple}[1]{#1^{T}}

makeatother



begin{document}



$transp A+transp{B+C}$



end{document}

documentclass{article}

usepackage{amsmath}

usepackage{xparse}



NewDocumentCommand{transp}{sm}{%

  IfBooleanTF{#1}{(#2)^{T}}{#2^{T}}%

}



begin{document}



$transp{A}+transp*{B+C}$



end{document}

share|improve this answer

answered 1 hour ago

egregegreg

723k8719163219

answered 1 hour ago

egregegreg

723k8719163219

answered 1 hour ago

egregegreg

723k8719163219

3

The following seems to work, but I doubt it is a good idea in general. Usually foo A and foo {A} give the same result for macros with one argument and the braces are needed in case the argument consists of more than one token. Indeed I would say that it is good practice to use braces for mandatory arguments even if they enclose only one token.

Note that transp without braces can only accept one token as its argument, so transp A+B is transp A and +B. In particular then, transp mathbf{A} dies horribly.

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifnextcharbgroup

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp A \

    transp{A}

  end{align*}

end{document}

A starred variant would be more common (see also egreg's answer)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifstar

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp*{A}

  end{align*}

end{document}

but you could also use an optional argument (p for parentheses, b for brackets)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand{transp}[2][]{%

  if#1p

    (#2)

  else

    if#1b

      [A]

    else

     A

    fi

  fi^{T}

}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp[b]{A}

  end{align*}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

moewemoewe

92.2k10115348

add a comment | 

3

The following seems to work, but I doubt it is a good idea in general. Usually foo A and foo {A} give the same result for macros with one argument and the braces are needed in case the argument consists of more than one token. Indeed I would say that it is good practice to use braces for mandatory arguments even if they enclose only one token.

Note that transp without braces can only accept one token as its argument, so transp A+B is transp A and +B. In particular then, transp mathbf{A} dies horribly.

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifnextcharbgroup

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp A \

    transp{A}

  end{align*}

end{document}

A starred variant would be more common (see also egreg's answer)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifstar

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp*{A}

  end{align*}

end{document}

but you could also use an optional argument (p for parentheses, b for brackets)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand{transp}[2][]{%

  if#1p

    (#2)

  else

    if#1b

      [A]

    else

     A

    fi

  fi^{T}

}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp[b]{A}

  end{align*}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

moewemoewe

92.2k10115348

add a comment | 

The following seems to work, but I doubt it is a good idea in general. Usually foo A and foo {A} give the same result for macros with one argument and the braces are needed in case the argument consists of more than one token. Indeed I would say that it is good practice to use braces for mandatory arguments even if they enclose only one token.

Note that transp without braces can only accept one token as its argument, so transp A+B is transp A and +B. In particular then, transp mathbf{A} dies horribly.

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifnextcharbgroup

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp A \

    transp{A}

  end{align*}

end{document}

A starred variant would be more common (see also egreg's answer)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifstar

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp*{A}

  end{align*}

end{document}

but you could also use an optional argument (p for parentheses, b for brackets)

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand{transp}[2][]{%

  if#1p

    (#2)

  else

    if#1b

      [A]

    else

     A

    fi

  fi^{T}

}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp[b]{A}

  end{align*}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

moewemoewe

92.2k10115348

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifnextcharbgroup

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp A \

    transp{A}

  end{align*}

end{document}

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand*{transp@nb}[1]{#1^{T}}

newcommand*{transp@br}[1]{(#1)^{T}}

newcommand{transp}{}

protecteddeftransp{%

  @ifstar

    {transp@br}

    {transp@nb}}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp*{A}

  end{align*}

end{document}

documentclass{article}

usepackage{amsmath}



makeatletter

newcommand{transp}[2][]{%

  if#1p

    (#2)

  else

    if#1b

      [A]

    else

     A

    fi

  fi^{T}

}

makeatother



begin{document}

  begin{align*}

    transp{A} \

    transp[b]{A}

  end{align*}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

moewemoewe

92.2k10115348

answered 1 hour ago

moewemoewe

92.2k10115348

answered 1 hour ago

moewemoewe

92.2k10115348