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How to apply float precision (type specifier) in a conditional f-string?

How do I check if a string is a number (float)?How do I parse a string to a float or int in Python?How to determine a Python variable's type?How do I trim whitespace from a Python string?How to check if type of a variable is string?How to lowercase a string in Python?How to read a text file into a string variable and strip newlines?SQLAlchemy Turning Floats Into Strings in SQL?Dictionary true/false errorConvert float to string without scientific notation and false precision

6

I have the following f-string I want to print out on the condition the variable is available:

f"Percent growth: {self.percent_growth if True else 'No data yet'}"

Which results in:

Percent growth : 0.19824077757643577

So normally I'd use a type specifier for float precision like this:

f'{self.percent_growth:.2f}'

Which would result in:

0.198

But that messes with the if-statement in this case. Either it fails because:

f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"

The if statement becomes unreachable.
Or in the second way:

f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"

The f-string fails whenever the condition leads to the else clause.

So my question is, how can I apply the float precision within the f-string when the f-string can result in two types?

python python-3.x f-string

share|improve this question

asked 4 hours ago

NoSplitSherlockNoSplitSherlock

1027

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I formulated the question this way so it was clear no matter what condition it fails to even execute.
  
  – NoSplitSherlock
  2 hours ago
  

  
  
  
  

add a comment | 

6

I have the following f-string I want to print out on the condition the variable is available:

f"Percent growth: {self.percent_growth if True else 'No data yet'}"

Which results in:

Percent growth : 0.19824077757643577

So normally I'd use a type specifier for float precision like this:

f'{self.percent_growth:.2f}'

Which would result in:

0.198

But that messes with the if-statement in this case. Either it fails because:

f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"

The if statement becomes unreachable.
Or in the second way:

f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"

The f-string fails whenever the condition leads to the else clause.

So my question is, how can I apply the float precision within the f-string when the f-string can result in two types?

python python-3.x f-string

share|improve this question

asked 4 hours ago

NoSplitSherlockNoSplitSherlock

1027

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I formulated the question this way so it was clear no matter what condition it fails to even execute.
  
  – NoSplitSherlock
  2 hours ago
  

  
  
  
  

add a comment | 

I have the following f-string I want to print out on the condition the variable is available:

f"Percent growth: {self.percent_growth if True else 'No data yet'}"

Which results in:

Percent growth : 0.19824077757643577

So normally I'd use a type specifier for float precision like this:

f'{self.percent_growth:.2f}'

Which would result in:

0.198

But that messes with the if-statement in this case. Either it fails because:

f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"

The if statement becomes unreachable.
Or in the second way:

f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"

The f-string fails whenever the condition leads to the else clause.

So my question is, how can I apply the float precision within the f-string when the f-string can result in two types?

python python-3.x f-string

share|improve this question

asked 4 hours ago

NoSplitSherlockNoSplitSherlock

1027

f"Percent growth: {self.percent_growth if True else 'No data yet'}"

Percent growth : 0.19824077757643577

f'{self.percent_growth:.2f}'

0.198

f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"

f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"

share|improve this question

asked 4 hours ago

NoSplitSherlockNoSplitSherlock

1027

share|improve this question

asked 4 hours ago

NoSplitSherlockNoSplitSherlock

1027

asked 4 hours ago

NoSplitSherlockNoSplitSherlock

1027

asked 4 hours ago

NoSplitSherlockNoSplitSherlock

1027

3 Answers
3

active

oldest

votes

7

You could use another f-string for your first condition:

f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"

Admittedly not ideal, but it does the job.

share|improve this answer

answered 4 hours ago

Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

1,216714

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.
  
  – Idlehands
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?
  
  – NoSplitSherlock
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @PatrickArtner Absolutely, that works too.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  

add a comment | 

2

You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:

for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)

    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")

    # you need to put '.05f' into a string for this to work and not complain

Output:

Percent growth: 2.56235

Percent growth: 0.90000

Percent growth: No data yet

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Patrick ArtnerPatrick Artner

24.9k62443

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I love how hacky this is.
  
  – NoSplitSherlock
  3 hours ago
  

  
  
  
  

add a comment | 

1

I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:

value = f'{self.percent_profit:.2f}' if True else 'No data yet'

print(f"Percent profit : {value}")

share|improve this answer

answered 4 hours ago

IdlehandsIdlehands

5,6551620

add a comment | 

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7

You could use another f-string for your first condition:

f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"

Admittedly not ideal, but it does the job.

share|improve this answer

answered 4 hours ago

Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

1,216714

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.
  
  – Idlehands
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?
  
  – NoSplitSherlock
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @PatrickArtner Absolutely, that works too.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  

add a comment | 

7

You could use another f-string for your first condition:

f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"

Admittedly not ideal, but it does the job.

share|improve this answer

answered 4 hours ago

Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

1,216714

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.
  
  – Idlehands
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?
  
  – NoSplitSherlock
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @PatrickArtner Absolutely, that works too.
  
  – Nikolas Stevenson-Molnar
  3 hours ago
  

  
  
  
  

add a comment | 

You could use another f-string for your first condition:

f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"

Admittedly not ideal, but it does the job.

share|improve this answer

answered 4 hours ago

Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

1,216714

f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"

share|improve this answer

answered 4 hours ago

Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

1,216714

answered 4 hours ago

Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

1,216714

answered 4 hours ago

Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

1,216714

2

You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:

for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)

    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")

    # you need to put '.05f' into a string for this to work and not complain

Output:

Percent growth: 2.56235

Percent growth: 0.90000

Percent growth: No data yet

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Patrick ArtnerPatrick Artner

24.9k62443

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I love how hacky this is.
  
  – NoSplitSherlock
  3 hours ago
  

  
  
  
  

add a comment | 

2

You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:

for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)

    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")

    # you need to put '.05f' into a string for this to work and not complain

Output:

Percent growth: 2.56235

Percent growth: 0.90000

Percent growth: No data yet

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Patrick ArtnerPatrick Artner

24.9k62443

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I love how hacky this is.
  
  – NoSplitSherlock
  3 hours ago
  

  
  
  
  

add a comment | 

You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:

for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)

    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")

    # you need to put '.05f' into a string for this to work and not complain

Output:

Percent growth: 2.56235

Percent growth: 0.90000

Percent growth: No data yet

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Patrick ArtnerPatrick Artner

24.9k62443

for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)

    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")

    # you need to put '.05f' into a string for this to work and not complain

Percent growth: 2.56235

Percent growth: 0.90000

Percent growth: No data yet

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Patrick ArtnerPatrick Artner

24.9k62443

answered 3 hours ago

Patrick ArtnerPatrick Artner

24.9k62443

answered 3 hours ago

Patrick ArtnerPatrick Artner

24.9k62443

1

I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:

value = f'{self.percent_profit:.2f}' if True else 'No data yet'

print(f"Percent profit : {value}")

share|improve this answer

answered 4 hours ago

IdlehandsIdlehands

5,6551620

add a comment | 

1

I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:

value = f'{self.percent_profit:.2f}' if True else 'No data yet'

print(f"Percent profit : {value}")

share|improve this answer

answered 4 hours ago

IdlehandsIdlehands

5,6551620

add a comment | 

I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:

value = f'{self.percent_profit:.2f}' if True else 'No data yet'

print(f"Percent profit : {value}")

share|improve this answer

answered 4 hours ago

IdlehandsIdlehands

5,6551620

value = f'{self.percent_profit:.2f}' if True else 'No data yet'

print(f"Percent profit : {value}")

share|improve this answer

answered 4 hours ago

IdlehandsIdlehands

5,6551620

answered 4 hours ago

IdlehandsIdlehands

5,6551620

answered 4 hours ago

IdlehandsIdlehands

5,6551620