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Coordinates unit in pt although default is cm in TikZ

Drawing simple 3D cylinders in TikZHow to make (1,1) mean (1cm,1cm) in TikZ? (Setting the units of coordinates)Rotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insideTikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themBest practice for creating TikZ pictures with nested elementsBaseline in TikZ default unit of lengthDefault tikz-3dplot main coordinates

2

As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm by default.

When I extract the coordinates, I was expecting the unit as cm. But TikZ shows the unit in the coordinate as pt.

How does TikZ determine the unit of measure in a coordinate if no unit is specified.

MWE:

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {(XCoord,YCoord)};

end{tikzpicture}



end{document} 

tikz-pgf unit-of-measure

share|improve this question

asked 5 hours ago

subham sonisubham soni

4,00582981

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
  
  – barbara beeton
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Barbara I would like to know the default unit of measure when unit of measure is not mentioned
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
  
  – marmot
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
  
  – zyy
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
  
  – marmot
  4 hours ago
  

  
  
  
  

 | 
show 7 more comments

2

As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm by default.

When I extract the coordinates, I was expecting the unit as cm. But TikZ shows the unit in the coordinate as pt.

How does TikZ determine the unit of measure in a coordinate if no unit is specified.

MWE:

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {(XCoord,YCoord)};

end{tikzpicture}



end{document} 

tikz-pgf unit-of-measure

share|improve this question

asked 5 hours ago

subham sonisubham soni

4,00582981

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
  
  – barbara beeton
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Barbara I would like to know the default unit of measure when unit of measure is not mentioned
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
  
  – marmot
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
  
  – zyy
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
  
  – marmot
  4 hours ago
  

  
  
  
  

 | 
show 7 more comments

As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm by default.

When I extract the coordinates, I was expecting the unit as cm. But TikZ shows the unit in the coordinate as pt.

How does TikZ determine the unit of measure in a coordinate if no unit is specified.

MWE:

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {(XCoord,YCoord)};

end{tikzpicture}



end{document} 

tikz-pgf unit-of-measure

share|improve this question

asked 5 hours ago

subham sonisubham soni

4,00582981

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {(XCoord,YCoord)};

end{tikzpicture}



end{document} 

share|improve this question

asked 5 hours ago

subham sonisubham soni

4,00582981

share|improve this question

asked 5 hours ago

subham sonisubham soni

4,00582981

asked 5 hours ago

subham sonisubham soni

4,00582981

asked 5 hours ago

subham sonisubham soni

4,00582981

1 Answer
1

active

oldest

votes

3

You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {%

  (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%

  pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};

end{tikzpicture}

end{document} 

share|improve this answer

answered 4 hours ago

marmotmarmot

104k4123236

add a comment | 

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3

You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {%

  (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%

  pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};

end{tikzpicture}

end{document} 

share|improve this answer

answered 4 hours ago

marmotmarmot

104k4123236

add a comment | 

3

You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {%

  (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%

  pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};

end{tikzpicture}

end{document} 

share|improve this answer

answered 4 hours ago

marmotmarmot

104k4123236

add a comment | 

You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {%

  (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%

  pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};

end{tikzpicture}

end{document} 

share|improve this answer

answered 4 hours ago

marmotmarmot

104k4123236

documentclass{article}

usepackage{tikz}

usetikzlibrary{decorations.pathmorphing}

usetikzlibrary{decorations.markings}

usetikzlibrary{calc}

usetikzlibrary{positioning}

tikzset{zigzag/.style={decorate,decoration=zigzag}}

begin{document}



newdimenXCoord

newdimenYCoord

newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}



begin{tikzpicture}

  coordinate (c) at (0,-2);

  coordinate (d) at (4,-2);

  coordinate (e) at (2,-4);

  draw[thick,red,zigzag,postaction={

    decoration={

        markings,

        mark=at position 0.7 with { coordinate (x); },

        mark=at position 0.5 with { coordinate (singularity); },

    },

    decorate

  }] (-2,0) coordinate(a) -- (2,0) coordinate(b);



  draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;

  draw[thick,postaction={

    decoration={

        markings,

        mark = at position 0.7 with coordinate (y);

    },

    decorate

  }] (a) -- (c);

  draw[thick,red,dashed] (x) -- (y);



  node[above = 10ex of singularity,red] (sn) {singularity};

  draw[red,->] (sn) -- ($(singularity)+(0,1)$);

  ExtractCoordinate{x};

  node[above] at (XCoord,YCoord) {%

  (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%

  pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};

end{tikzpicture}

end{document} 

share|improve this answer

answered 4 hours ago

marmotmarmot

104k4123236

answered 4 hours ago

marmotmarmot

104k4123236

answered 4 hours ago

marmotmarmot

104k4123236